Question

1. A and B can do a work in 18 and
24 days respectively. They
worked together for 8 days and
then A left. The remaining work
was finished by B in :
1
-days
(1) 5 days
geer (3) 8 days
(4) 10 days
Maaga 1

Answer 1

Step-by-step explanation:

Together they can do =1/18+1/24=(4+3)/72=7/72

if they work for 8 days

(7/72)×8=7/9 part of work

left part=2/9 will be done by B alone

(2/9)×24=16/3days=5days

Answer 2

Answer:

$\frac{16}{3}$ days

Step-by-step explanation:

Complete work done by A= 18 days.

In one day A can do  $\frac {1}{18}$ part of the work.

Complete work done by B = 24 days.

In one day B can do= $\frac {1}{24}$ part of the work.

One day work of A and B

$= \frac {1}{18} + \frac{1}{24}$

$=\frac {4+3}{72}$

$=\frac {7}{72}$

They worked for 8 days,

Work done by A and B in 8 days

$=8\times {\frac {7}{72}}$

$=\frac {56}{72}$

$=\frac {7}{9}$

Now, A left the work

Remaining work

$=1- \frac {7}{9}$

$=\frac {2}{9}$

Remaining work done by B in

$=\frac{\frac{2}{9}}{\frac{1}{24}}$

$=\frac {2}{9} \times \frac {24}{1}$

$=\frac {16}{3}$

So, remaining work done by B in $\frac {16}{3}$ days.