1/(a+b+x) =1/a + 1/b + 1/x.
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1/(a+b+x)=1/a+1/b+1/x
(1/a+b+x)-1/x=1/a+1/b
x-a-b-x/ax+bx+x^2=b+a/ab
-a-b/x^2+ax+bx=a+b/ab
-(a+b)(ab)=(a+b)(x^2+ax+bx)
-(a+b)/(ab)*(ab)=x^2+ax+bx
-ab=x^2+ax+bx
x^2+(a+b)x+ab=0
x^2+ax+bx+ab=0
x(x+a)+b(x+a)=0
(x+b)(x+a)=0
x=-b
x=-a.
i hope this is helpful to you
(1/a+b+x)-1/x=1/a+1/b
x-a-b-x/ax+bx+x^2=b+a/ab
-a-b/x^2+ax+bx=a+b/ab
-(a+b)(ab)=(a+b)(x^2+ax+bx)
-(a+b)/(ab)*(ab)=x^2+ax+bx
-ab=x^2+ax+bx
x^2+(a+b)x+ab=0
x^2+ax+bx+ab=0
x(x+a)+b(x+a)=0
(x+b)(x+a)=0
x=-b
x=-a.
i hope this is helpful to you
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