1/a+b+x=1/a+1/b+1/x find the value of x
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I think it will be helpful to you ..
[(1/a-1/a) + (b-1/b)] = (1/x-x)
[(b^2 - 1)/b] = (1-x^2)/x
(b^2)x - x = b - (x^2)b
the value of x will be 1/b and -b .///
[(1/a-1/a) + (b-1/b)] = (1/x-x)
[(b^2 - 1)/b] = (1-x^2)/x
(b^2)x - x = b - (x^2)b
the value of x will be 1/b and -b .///
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Answered by
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1/a+b+x = 1/a+1/b+1/x
1/a+b+x = bx+ax+ab/abx
(a+b+x) (bx+ax+ab) = abx
abx+a²x+a²b+b²x+abx+ab²+bx²+ax²+abx = abx
(a+b)x² + (a²+b²)x + 3abx-abx + ab(a+b) = 0
(a+b)x² + (a²+b²)x + 2abx + ab(a+b) = 0
(a+b)x² + (a²+b²+2ab)x + ab(a+b) = 0
(a+b)x² + (a+b)²x + ab(a+b) = 0
(a+b) [x²+(a+b)x+ab] = 0
(a+b) [x²+ax+bx+ab] = 0
(a+b) [x(x+a)+b(x+a)] = 0
(a+b) [(x+a)(x+b) ] = 0
(x+a)(x+b) = 0/(a+b)
(x+a)(x+b)=0
x = -a and x = -b
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