Math, asked by firozkiresur, 11 months ago

1/a+b+x=1/a+1/b+1/x solve for x

(where a not equal to 0, b not eq to 0, x not equal to 0, x not equal to -(a+b)​

Answers

Answered by mayapandey287
0

Answer:

height of cone, h=8m

CSA of cone = 188.4 metre sq.

πrl=188.4 m^2

l=188.4/3.14 r

l= 60/ r

we know that,

{r}^{2} = {l}^{2} - {h }^{2}r

2

=l

2

−h

2

r^2=(60/r)^2 -8^2

r^2 =3600/r^2 -64

r^4 + 64r^2 -3600=0

Let r^2 =R to Simplify the equation a little

R^2 + 64R -3600=0

Solving this ,we get;

R=36

therefore... r=6

Now, Volume of a cone :

{\pi {r}^{2} h} \div 3πr

2

h÷3

=(3.14 *6*6*8)/3

=301.44 m^3

Step-by-step explanation:

volume \: of \: cone \: =301.44 \: {m}^{3}volumeofcone=301.44m

3

Hope you get dear....

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