Question

1. A ball moves on a smooth floor in a straight
line with uniform velocity 10 m s-l for 6 s. At
t = 6 s, the ball hits a wall and comes back
along the same line to the starting point with
same speed. Draw the velocity-time graph and
use it to find the total distance travelled by the
ball and its displacement.​

Answer 1

Answer:

This is the required v - t graph

So distance will be equal for both forward and backward position

d=v×t

d=10×6

so total distance is D=2d=120m

and

displacement=0

because initial and final position are same.

solution

Answer 2

Explanation:

Distance travelled in first 6s = velocity × time

=10m/s × 6

= 60 m/s

Distance travelled in next 6s = velocity × time

= 10 m/s × 6

= 60 m/s

Total Distance travelled in 12s = 60+60

= 120 m

Total displacement = 0 (as the ball returns it's starting point)