1. A ball of mass 100 gm moving with speed of 20 m/s is turned back with same speed in 0.1 s. The
impulse on the ball is?
(A) 4 Ns (B) 2 Ns
(C) 40 Ns
(D) 20 Ns
Answers
Answered by
3
Answer:
c )40 NS
Explanation:
Impulse = 2mv×t
Answered by
3
Mass of the ball = 100 gm
Velocity of the ball before collision = 20m/s
So , momentum = mv = 0.1*20 = 2 kg m/s
Velocity of the ball after collision = -20m/s ( -ve sign indicates the opposite direction )
therefore , final momentum = m(-v) = 0.1 * (-20) = -2 kg m/s
impulse = change in momentum
= final momentum - initial momentum
= -2 -2
= -4 kg m/s
Hope it will help you .
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