1.) A beam of light hits at an angle of 35 degrees to the mirror surface. Determine the angle of reflection?
2.) A beam of light travels from air to water. If the refractive index for water is 1.5; the refractive index of air is 1 and the speed of light propagation in the air is 3 × 10 ^ 8. So determine the speed of light propagation in water?
please answer? please use this method please .......!
Answers
No.1
Known:
angle of view = 35⁰
Asked: large angle of reflected light
Answered:
According to the law of light reflection:
1. incident ray, reflected ray, and normal lines lie on one flat plane
2. the incident angle of light (i) is the same as the angle of reflection (r)
So that the angle of reflection is the same is 35⁰
No.2
Known :
na = 1.5
nu = 1
vu = 3x10⁸ m / s
Asked: Va?
Answered:
Va / Vu = nu / na
Va / 3x10⁸ = 1 / 1.5
Va = 1 / 1.5 x 3x10⁸
Va = 2x10⁸ m / s
Step-by-step explanation:
Answer to Question no. 1 : Accordind to the laws of reflection, the angle of reflection is going to be the sane i. e., 35 degrees.
Answer to question 2: Refractive index is the ratio of speed of light in one and light through the second medium.
n=c/v
where n is the refractive, 'c' is the speed of light and 'v' is the velocity of light in the second medium.
therefore n=c/v
1.5=3*10'8/v
on solving this we get v=2*10,8 m/s.