Question

1. A body is moving with a uniform velocity of 10 ms"
on a circular path of diameter 2.0 m. Calculate
(n the difference between the magnitude of the
displacement of the body and the distance covered
in half a round and (ii) the magnitude of the change
in velocity of the body in half a round.​

Answer 1

Explanation:

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Answer 2

Given:

The uniform velocity of the body is $10 \ m/s$.

The diameter of the circular path is $2.0 \ m$

To Find:

(i) The difference between the magnitude of the displacement of the body and the distance covered.

(ii) The magnitude of the change in velocity of the body in half a round.​

Solution:

(i) Displacement of the body = shortest distance from the starting position to the ending position.

Therefore, displacement = $2.0 \ m$

Distance covered = circumference of semic-circle.

Therefore, distance = π $\times$ r = $3.14 \times 1 = 3.14$

Difference between the two = $3.14 - 2.0 = 1.14$ m

(ii) velocity = $\frac{displacement}{time}$

= $\frac{2}{0.314}$

= $6.26 \ m/s$

Therefore, the rate of change = $10 - 6.36 =3.64 \ m/s$

Hence, the difference between the displacement and the distance covered is $1.14 \ m$ and the magnitude of the change in velocity of the body in half a round is $3.64 \ m/s$.

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