Question

1. A body is projected horizontally with speed 5 m/s
from height h, takes 8 s to reach the ground. The
time it takes to cover the first one fourth of height​

Answer 1

$\huge\boxed{\mathfrak{\fcolorbox{red}{yellow}{answer}}} </p><p>$

$\large{\boxed{\bf{T' \: = \: 2s}}}$

$\huge\boxed{\mathfrak{\fcolorbox{red}{yellow}{solution}}}</p><p></p><p></p><p>[tex]$

Relation b/w time and height is

$\large{\boxed {\sf{\red{T \: = \: \sqrt{\frac{2H}{g}}}}}}$

$\: \: \: \mapsto{\sf{H \: = \: height}}</h3><h3> \\ \ \mapsto{\sf{T \: = time}} \\ \: \: \: \mapsto{\sf{g \: = \: gravity}}$

${\sf{«solving \: ahead \: as \: per \: question»}}$

$\large \frac{T'}{T} = \frac{H'}{H}$

$\bull{\sf{T' \: \: = \: ? \: \:}}$

$\bull{\sf{T \: = 8s}}$

$\bull{\sf{H' \: \: = h/4}}$

$\bull{\sf{H\: = h }}$

$\large \frac{T'}{8} = \frac{h}{4h}$

Solving ,

$\large{\boxed{\bf{T' \: = \: 2s}}}$