Physics, asked by kvparikshith, 5 months ago

1. A body of mass 1 kg is kept at rest. A constant force of 6 N starts acting on
it. Find the time taken by the body to move through a distance of 12 m.

Answers

Answered by Anonymous
51

Answer :-

Given :-

  • Initial velocity = 0 m/s
  • Mass = 1 kg
  • Force = 6 N
  • Distance = 12 m

To Find :-

  • Time taken

Solution :-

To find time, we first need to find acceleration and then substitute the value of given in the second equation of motion -

➩ Force = Mass × Acceleration

➩ 6 = 1 × a

a = 6 m/s²

  • u = 0
  • a = 6 m/s²
  • s = 12 m

Substituting the value in 2nd equation of motion :-

➩ s = ut + 1/2 at²

➩ 12 = 0 + 1/2 × 6 × t²

➩ 12 = 3t²

➩ t² = 12/3

➩ t² = 4

➩ t = 2 sec

Time taken = 2 sec

Answered by Anonymous
62

Given :-

\\

  • Initial Velocity = 0 m/s
  • Mass = 1 kg
  • Force = 6 N
  • Distance = 12 m

\\

To find :-

\\

  • Find the Time Taken ?

\\

Solution :-

\\

  • Find Time Taken, We first need to find acceleration and then substitute the value of given in the second equation of motion.

\\

\underline{\bf{\bigstar} \: \mathfrak{As \: we \: know \: that}}

\\

\boxed{\bf{Force~=~Mass~×~Acceleration}}

\\

  • \large\dashrightarrow6 = 1 × a
  • \large\dashrightarrow a = 6 m/s²

\\

  • \large\mapsto0
  • \large\mapsto6 m/s²
  • \large\mapsto12 m

\\

Substituting the value,

\\

  • 2nd equation of motion.

\\

:\impliess = \large{\sf{ut \:  +  \:  \frac{1}{2} \: at²}}

\\

~~~~~:\implies\large{\sf{0 \: + \: \frac{1}{2} \: \times \: 6 \: \times t²}}

\\

~~~~~~~~~~:\implies12 = 3t²

\\

~~~~~~~~~~~~~~~:\impliest² = \large{\sf{\frac{12}{3}}}

\\

~~~~~~~~~~~~~~~~~~~~:\impliest² = {\sf{\dfrac{\cancel{12}}{\cancel{3}}}}

\\

~~~~~~~~~~~~~~~~~~~~~~~~~:\implies \large{\underline{\boxed{\pink{\frak{t~=~2~sec}}}}}

\\

\large\dag Hence,

\\

  • Time Taken = \large\underline{\rm{2~sec}}\large{\bf\green{✓}}
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