Question

1. A body of mass 20 kg is suspended by a light string wound round a pulley of mass 50 kg
Find acceleration of the body and pull in the string.
[Ans. 4.36 m/s2, 108.9 N​

Answer 1

Answer:

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Explanation:

Correct option is

A

=0

As the lift is freely falling, thus its acceleration in down ward direction a=g

Let the mass of the body be m and force acting on it due to spring be F.

Writing equation of motion for the body : m a=mg−F

Or mg=mg−F

⟹ F=0

Thus no force is acting on the body due to spring, so the reading of the spring balance is zero