Question

1. A bus starting from rest moves
with a uniform acceleration of
0.1 m s2 for 2 minutes. Find (a)
the speed acquired, (b) the
distance travelled.
​

Answer 1

constant acceleration=constant velocity

velocity=0.1m/s.

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Answer 2

Answer:

The speed acquired by bus is 12 m/s.

The distance travelled by bus is 720 m.

Explanation:

Given,

✤ Initial velocity (u) = 0

✤ Acceleration (a) = 0.1 ms^-2

✤ Time (t) = 2 minutes = 120 seconds

(i) Firstly, we have to find the speed acquired by the bus, by first equation of motion :

❖ $\large\fbox{\sf v = u + at}$

→ $\sf{v = 0 + 0.1 \times 120 }$

→ $\fbox{\sf v = 12 m/s}$

(ii) Now, we will find the distance travelled by bus, by second equation of motion :

❖ $\large\fbox{\sf s = ut + \frac{1}{2} at^2}$

→ $\sf{s = 12 + \frac{1}{2} \times 0.1 \times 12}$

→ $\fbox{\sf 720\:m}$

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