Question

1. A car is uniformly accelerated from 18 kilometre per hour to 36 km per hour in 5 seconds calculate the acceleration.

Answer 1

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$\boxed{Given :- }$

$\underline{Initial \: Velocity (\:U) =}$ 18km/h =》 5m/s

$\underline{Final \:Velocity ( \:V) =}$ 36km/h =》 10m/s

To find acceleration we will use the formula

$a = \frac{v - u}{t}$

Where V = final Velocity, U = Initial Velocity,
t = time , a = acceleration .

$a = \frac{v - u}{t}$


$a = \frac{10 - 5}{5}$


$a = \frac{5}{5}$


$a = 1m {s}^{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{ans}$

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Hope this helps. . . . . .

Answer 2

Answer:

Given that:-

Time taken (t) = 5 sec

Initial velocity (u) =18 km/hour

\(u = \frac{18\times 1000}{60\times 60s}\)

u = 5 m/s

Final velocity (v) =36km/hour

\(v = \frac{36\times 1000}{60\times 60s}\)

v =10 m/s

We need to calculate acceleration and distance traveled

We know that

acceleration a = (v – u)/t

Substituting the given values in the above equation we get,

a = (10 – 5)/5

a =5/5

a = 1 m/s2

We know that distance travelled is calculated by the formula

Distance travelled S = u t + (1/2) a × t2

Substituting the given values in the above equation we get,

S = 5 × 5 + (1/2) × 1 × 52

S = 25 + (1/2) × 25

S = 25 + 12.5

S = 37.5 m

Hence

acceleration a =1 m/s2

Distance travelled S =37.5 m