Math, asked by satishpanipat1969, 10 months ago

1.
A
contractor
employed
25
labourers
on
a
job
.
He
was
paid
275
for
the
work
.
After
retaining
20
%
of
this
sum
,
he
distributed
the
remaining
amount
amongst
the
labourers
.
If
the
number
of
men
to
women labourers was in the ratio 2 : 3 and their
wages in the ratio 5: 4. What wages did a woman
labourer get?
(b) 8
(c)? 12 (d) 15​

Answers

Answered by ratansinghrawat9090
0

Answer:

been trying my phone number

Answered by aden44
1

Answer:

8

Step-by-step explanation:

As mentioned in the question,

Number of men = 25×25 =10

Number of women = 35×25 =15

Step 1:

Amount distributed among men and women

= 275×80% = Rs.220

Step 2:

Let the wages paid to a man by 5p and to woman be 4p,

=> 10×5p+15×4p = 220

=> 50p + 60p = 220

=> p = 2

Therefore, Wages received by a woman =

2×4 = 8 rupees.

Similar questions