Question

1) A cricket ball of mass 100g moving with a speed of 30mls is brought to test by the player. Find the change in momentum of the ball.​

Answer 1

$\red{\textbf{Answer :- -100}}$

Explanation:

$\red{\textbf{Given :-}}$

Mass=0.1kg

Initial Momentum=m×speed (u)

=0.1×30 =3

Final Momentum= m×rest (v)

=0.1×0 =0

Change in Momentum= Final-Initial =

0−3=−3

Rate of change in momentum

=(change in momentum)÷time taken

=(−3)÷0.03

=−100

$\red{\textbf{rate of change in momentum is -100}}$

$\blue{\textbf{More information :-}}$

• The rate of change of the total momentum of a system of particles is equal to the sum of the external forces on the system.

• An object's momentum is the product of its velocity and mass.