1+a cube+b cube +3ab
Factorise this
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Answer:
We know the algebraic identity ,
x³ + y³ + z³ - 3xyz
= ( x + y + z )( x² + y² + z² - xy - yz - zx )
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Now ,
a³ - b³ + 1 +3ab
= a³ + ( - b )³ + 1³ - 3 × a × ( - b ) × 1
= [ a+(-b)+1 ][a²+(-b)²+1²-a(-b)-(-b)1-1×a]
= ( a - b + 1 ) ( a² + b² + 1 + ab + b - a )
Read more on Brainly.in - https://brainly.in/question/1239515#readmore
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