Question

1. A cyclist starting from rest covers a diatance of 100m in 5 seconds.assuming his acceleration is uniform,calculate his velocity at
(a) the end of 5 seconds.
(b) distance travelled in 5th second
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Answer 1

Answer:

Total distance =100m

Total time =5 seconds

u=0

1) s=ut +1/2 at2

100 = 1/2×a×(5)2

100=1/2×a×25

100×2/25 =a

a=8m/s2

v=u+at

v=8×5

v=40m/s

2)s=u+a/2(2n-1)

=8/2[2(8)-1]

=4(17)

=68 m

ANSWER