Question

inser A.M.s between 7 and 71 in such a way that the 5th A.M. is 27. find the number of A.M.s.

Answer 1

$\huge{Hey Mate!!!}$

⭐⭐Here is ur answer ⭐⭐

Here , a=7 , c=71    [ Where 'a' 1st term of A.P. & 'c' last term]

5th A.M. is = 27

         a+5d=27         [ d= common difference]

         7+5d=27

              5d=20

                 d=4

 Now we have, d=(c-a)/(n+1)  [ n=Number of A.M]

                           4=(71-7)/(n+1)

                   4(n+1)=64

                           4n =60

                             n=15

Therefor number of A.M. is 15 

CHEERS!!!

Answer 2

$\huge{Hello Friend}$

The answer of u r question is..✌️✌️


Ans:✍️✍️✍️✍️✍️✍️✍️✍️✍️

Here,

a= 7

c= 71

5th A.S.M = 27

a+5d=27

7+5d=27

5d=27+7

5d= 20

D=20/5

d=4

1d= (c-a)/n+1

$4 = \frac{(71 - 7)}{n + 1}$


4(n+1)=64

4n= 65

n= 15

$\huge{Thank you}$