What is the value of (cos^2 67°- sin^2 23°)?
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COS^2 67 - SIN^2 23
COS^2 [90-67] -SIN^2 23
SIN^2 23 -SIN^2 23
0
COS^2 [90-67] -SIN^2 23
SIN^2 23 -SIN^2 23
0
Ishikachauhan83:
Thnku. .
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To find:
Cos^2 67 - Sin^2 23
Solution:
By formula,
Cos^2A - Sin^2B = Cos ( A + B ) * Cos ( A - B )
Here,
A = 67
B = 23
Substituting,
We get,
Cos (67 + 23 ) * Cos( 67 - 23 )
Cos ( 90 ) * cos ( 45 )
Substituting values,
0 * 1/√2 .
Hence, Cos^2 67 - Sin^2 23 = 0
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