Math, asked by Ishikachauhan83, 1 year ago

What is the value of (cos^2 67°- sin^2 23°)?

Answers

Answered by muskanbaksh
1
COS^2 67 - SIN^2 23
COS^2 [90-67] -SIN^2 23
SIN^2 23 -SIN^2 23
0

Ishikachauhan83: Thnku. .
muskanbaksh: wlcme
Answered by topanswers
0

To find:

Cos^2 67 -  Sin^2 23

Solution:

By formula,

Cos^2A - Sin^2B = Cos ( A + B ) * Cos ( A - B )

Here,

A = 67

B = 23  

Substituting,

We get,

Cos (67 + 23 ) * Cos( 67 - 23 )

Cos ( 90 ) * cos ( 45  )

Substituting values,

0 * 1/√2 .

Hence, Cos^2 67 -  Sin^2 23 = 0

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