Math, asked by ashasolanki5, 8 months ago

1. A diagonal of a quadrilateral is 50 cm long
and the length of the perpendiculars on it
from the opposite vertices is 15 cm and 17
cm. Find the area of the quadrilateral.
1.1...be of​

Answers

Answered by Rishi3000
1

Answer:

800 sqcm

Step-by-step explanation:

1/2 * one of the diagnol * (sum of perpendiculars)

1/2*50*(15+17)

25*32

800sq cm

Answered by hbbhalekar65gmailcom
0

Step-by-step explanation:

Question :

Find the area of a rhombus, the lengths of

whose diagonals are 44 cm and 26 cm.

Answer :

\sf\pink{Given:}Given:

Diagonal of rhombus are 44 cm and 26 cm .

\sf\pink{To\:Find:}ToFind:

Area of rhombus = ?

Explanation :

\bf\purple{Area\:of\: rhombus = \dfrac{1}{2}\times diagonal 1\times diagonal 2}Areaofrhombus=

2

1

×diagonal1×diagonal2

\longrightarrow\bf{\dfrac{1}{2}\times 44\times 26}⟶

2

1

×44×26

\longrightarrow\bf{22\times 26}⟶22×26

\longrightarrow\bf{572}⟶572

Therefore area of the rhombus is 572 cm²

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