1)
a) Draw the sequence of equilateral triangle, square, regular pentagon,regular hexagon ....
b) Write the interior angle sum as a sequence
c) Write the sequence of one interior angle
d) Write the measure of exterior angle as a sequence
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0
Answer:
We know that each interior angle of a regular polygon is given by 180
o
−
n
360
o
, n= number of sides
Here for pentagon, Each interior angle=180
o
−
5
360
o
=108
o
From figure in ΔABE−
A=108
o
And, ∠ABE=∠AEB since AB=AE
⟹∠ABE+∠AEB+∠A=180
o
⟹∠ABE+∠AEB+108
o
=180
o
⟹∠ABE=∠AEB=36
o
Hence,a=36
o
Similarly from ΔBCD−
∠CBD=∠CDB=36
o
Now ∠CBA=∠ABE+∠EBD+∠CBD
⟹108
o
=36
o
+∠EBD+36
o
⟹∠EBD=b=36
o
Now in ΔBCD−
∠CDE=∠CDB+c
⟹108
o
=36
o
+c
⟹c=72
o
Hence c=2a=2b where b=36
o
Answered by
1
Initial level of water v
i
=55 ml
Final level of water v
f
=83ml
Volume of stone V
stone
=V
f
−V
i
=83−55=28 ml
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