Physics, asked by mdtariqueksa966, 7 months ago

If 50 kN load is applied on steel rod of cross sectional area 400 mm2, stress will be

Answers

Answered by gamerchiru395

2

Answer:

Mass = 50KN = 50,000N

Area = 400mm2

Stress = Force /Area

= 50000/400

= 125pa

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