Question

1) A fast-food restaurant sells hamburgers at 15 pesos each and hot dogs at 10 pesos each.
a. Write an algebraic expression to find the total sales revenue if the fast food restaurant
y hot dogs.
b. What is the total sales revenue of the fast-food restaurant if x=30 and y=45​

Answer 1

Appropriate Question:

A fast-food restaurant sells hamburgers at 15 pesos each and hot dogs at 10 pesos each.

a. Write an algebraic expression to find the total sales revenue if the fast food restaurant sales x hamburgers and y hot dogs.

b. What is the total sales revenue of the fast - food restaurant if x = 30 and y = 45.

Answer:

$\boxed{\begin{aligned}& \qquad \:\sf \: a. \: \: Total\:sale\:revenue = (15x + 10y) \: pesos\qquad \: \\ \\& \qquad \:\sf \: b. \: \: Total\:sale\:revenue = 900 \: pesos\end{aligned}} \qquad$

Step-by-step explanation:

Given that,

$\sf \: Selling\:price \: of \: 1 \: hamburger = 15 \: pesos$

So,

$\sf \: Selling\:price \: of \: x \: hamburgers = 15x \: pesos$

Further given that,

$\sf \: Selling\:price \: of \:1\: hotdog = 10 \: pesos$

So,

$\sf \: Selling\:price \: of \:y\: hotdogs = 10y \: pesos$

Thus,

$\implies\sf \: Total\:sale\:revenue = (15x + 10y) \: pesos$

On substituting the values of x = 30 and y = 45, we get

$\sf \: Total\:sale\:revenue$

$\sf \: = \: 15 \times 30 + 10 \times 45$

$\sf \: = \: 450 + 450$

$\sf \: = \: 900 \: pesos$

Hence,

$\implies\sf \: \boxed{\bf \: Total\:sale\:revenue = \: 900 \: pesos \: }$

Hence,

$\boxed{\begin{aligned}& \qquad \:\sf \: a. \: \: Total\:sale\:revenue = (15x + 10y) \: pesos\qquad \: \\ \\& \qquad \:\sf \: b. \: \: Total\:sale\:revenue = 900 \: pesos\end{aligned}} \qquad$