Physics, asked by suddeeksha, 1 year ago

1. A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?

2. A person hammer with a force of 2.5N on a nail of an area of its tip of 0.001mm2, Find the pressure exerted on wood when it is nailed into wood.

Answers

Answered by Anonymous
2

If Force = F = 1200 N

Area = A = 10 cm²  

A = 10 cm² = 10 X 10 -4 m² = 10 -3 m²  

Thrust = Normal Pressure = F = 1200 N  

Pressure P = F / A = 1200 N / 10 -3 m² = 1.2 x 10 6 N/ m²





suddeeksha: what about the 2 question
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