1. A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?
2. A person hammer with a force of 2.5N on a nail of an area of its tip of 0.001mm2, Find the pressure exerted on wood when it is nailed into wood.
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If Force = F = 1200 N
Area = A = 10 cm²
A = 10 cm² = 10 X 10 -4 m² = 10 -3 m²
Thrust = Normal Pressure = F = 1200 N
Pressure P = F / A = 1200 N / 10 -3 m² = 1.2 x 10 6 N/ m²
suddeeksha:
what about the 2 question
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