Question

1. A function is defined by f(x) =
3x2 + 2x - 1
, X e R, X 6-1. Find the value of f(-3) +1.
​

Answer 1

Answer:

This right answer.

Step-by-step explanation:

please give me brilliant mark

Answer 2

Answer:

The value f(-3) + 1 where the function  $f(x) = \frac{3x^2 + 2x -1}{x+1}$  is -9.

Step-by-step explanation:

An expression, rule, or law in mathematics that specifies the relationship between an independent variable and a dependent variable (the dependent variable).

The functions are commonly written as y = f(x), called "f of x" and x & y are related such that they have unique values. This means that the same x cannot have more than one value for f(x). An element x is connected to an element f(x) in another set by a function, to use the language of set theory. The range of the function is the set of values of f(x) that are produced by the values in the domain, whereas the set of values of x for which the function is defined is referred to as the domain.

Given, The function is

$f(x) = \frac{3x^2 + 2x -1}{x+1}$

f(-3) = [3(-3)² + 2(-3) -1]/[-3 + 1]

f(-3) = (27 -6 - 1)/(-2)

f(-3) = -20/2

f(-3) = -10

So, f(-3) + 1 = -10 + 1 = -9

Hence, the value f(-3) + 1 is -9.

To learn more about the function, click on the link below:

https://brainly.in/question/222093

To learn more about the domain, click on the link below:

https://brainly.in/question/11665021

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