Question

write down electronic configuration of Nacl​

Answer 1

Answer:

In writing the electron configuration for sodium the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for sodium go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the remaining electron in the 3s. Therefore the sodium electron configuration will be 1s

2

2s

2

2p

6

3s

1

=[Ne]3s

1

In writing the electron configuration for Chlorine the first two electrons will go in the 1s orbital. Since 1s can only hold two electrons the next 2 electrons for Chlorine go in the 2s orbital. The next six electrons will go in the 2p orbital. The p orbital can hold up to six electrons. We'll put six in the 2p orbital and then put the next two electrons in the 3s. After filling 3s we'll move to the 3p where we'll place the remaining five electrons. Therefore the Chlorine electron configuration will be 1s

2

2s

2

2p

6

3s

2

3p

5

=[Ne]3s

2

3p

5

Note: [1s

2

2s

2

2p

6

=[Ne]] is the electronic configuration of noble gas Ne.

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Answer 2

Answer:

The electron configuration of sodium and chloride ions- the components of table salt ( Nacl) provide a useful insight to the octet rule. Sodium ( Na) with an electron configuration of 1s2 2s2 2p6 3s1 sheds its outermost 3s electron and, as a result, the na+ ion has an electron configuration of 1s2 2s2 2p6.

Explanation:

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