1. A girl walks 500 m towards east and then 1200 m towards north. Find her distance from the starting point.
Answers
Answered by
3
It clearly forms a triangle if we join the starting and end points.Therefore by Pythagoras theorem,x² = 1200² + 500²
x² = 1440000 + 250000
x² = 1690000
∴ x = 1300
Therefore, the distance(x) from the starting point = 1300 m
Hope it helps ! :)
x² = 1440000 + 250000
x² = 1690000
∴ x = 1300
Therefore, the distance(x) from the starting point = 1300 m
Hope it helps ! :)
Answered by
1
if we draw the lines it becomes a right angle triangle
let the distance from starting point be ×
so by pythagoras theorem
×^2=500^2+1200^2
×^2=250000+144000
×^2=1690000
×=1300
therefore the distance from starting point is 1300
let the distance from starting point be ×
so by pythagoras theorem
×^2=500^2+1200^2
×^2=250000+144000
×^2=1690000
×=1300
therefore the distance from starting point is 1300
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