Question

*(1) (a) How much heat energy is necessary to raise
the temperature of 5 kg of water from 20°C to
100 °C.​

Answer 1

Answer:

Given :

Mass =5kg

T

1

=20

∘

C,T

2

=100

∘

C

ΔT=100−20=80

∘

C

Q=m×C×ΔT

where C= specific heat capacity of water

=4200J/(kgK)

Q=5×4200×80

=1680000 Joule.

=1680KJ

Explanation:

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