Question

1. A Japanese bullet train decelerates at a constant rate in a straight line. The velocity of the
train decreases from 50 m/s to 42 m/s in 30 seconds.
(a) Calculate the change in velocity of the train.

Answer 1

Anѕwєr :

– 8 m/s

Explαnαtion :

As per the provided information in the given question, we have :

• The velocity of the train decreases from 50 m/s to 42 m/s in 30 seconds.

Basically from this statement, it can be extracted that :

• Initial Velocity, u = 50 m/s
• Final Velocity, v = 42 m/s
• Time Taken, t = 30 seconds

We've been asked to calculate the change in velocity.

The change in velocity of the train is calculated by finding the difference of final velocity and initial velocity. i.e,

$\longrightarrow \sf{\Delta v = v_f - v_i}$

$\longrightarrow \sf{\Delta v = v- u}$

$\longrightarrow \sf{\Delta v = (42 - 50) \; m\: s^{-1}}$

$\longrightarrow\boxed{\red{\sf{ \Delta v = -8 \;m\:s^{-1} }}}$

∴ The change in velocity of the train is – 8 m/s.

$\rule{200}2$

Answer 2

Answer:

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