Question

(1) A lens produces a magnification of -0.5. Is this a converging or diverging
lens? If the focal length of the lens is 6 cm, draw a ray diagram showing the
image formation in this case.​

Answer 1

Answer:

it is a convex lens and the ray diagram will be as shown in the image

Answer 2

Answer:

Explanation:

Since the Magnification is negative, the given lens is a Converging Lens or in other words a Convex Lens.

m=$\frac{v}{u}$

$\frac{-1}{2}$ = $\frac{v}{u}$

2v = -u -----> 1

$\frac{1}{f}$ = $\frac{1}{v}$ - $\frac{1}{u}$

$\frac{1}{6}$ = $\frac{1}{v}$ + $\frac{1}{2v}$ [From 1]

$\frac{1}{6}$ = $\frac{2}{2v}$ + $\frac{1}{2v}$ [LCM]

$\frac{1}{6}$ = $\frac{3}{2v}$

2v = 18 [Cross Multiplication]

v = 9cm -------> 2

Substituting 2 in 1

-u = 18

u = -18