1. A liquid drop has 20 excess electrons. Calculate the charge on the liquid drop.
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Answer:
The initial charge of protons and electrons balance each other therefore initial charge of drop is 0
but when 20 extra electrons are added it aquires a negative charge of following value
charge of 1 e =1.6*10^-19 C
therefore charge due to 20 e = 20 * 1.6*10^-19 C
= 3.2*10^-18 C
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