Question

29. 9 men and 12 women, working 7hour a day complete 3/4ths of a job in 4 days and the remaining part of job is done by 12men and 7 women in 2 days working 5hours a day in how many days would the entire job be done by 6 men and 14 women working 8 hours a day?​

Answer 1

Answer:

The work is completed in 5 days.

So, the amount of work done by 12 men in 1 day is 1/5.

12 men work for 8 hrs a day.

So, work done by 12 men in 1 hour is (1/5)*(1/8) = 1/40.

Now, work done by a man in an hour will be (1/40)/12 = 1/480.

According to the question, the work is to be completed in 5 days by working for 10 hours a day.

Therefore, let us assume x men work each day.

Work done by x men in 10 hours(i.e, 1 day) will be x*(1/480)*10 = x/(48).

Then, amount of work done in 5 days = (x/(48))* 5

= 5x/48.

Now, if the work is to be completed, the fraction of work to be done in 5 days will be 1.

Therefore, 5x/(48) = 1

x = 48/5

x = 9.6

i.e, it requires 9.6 men (approximately 10 men) to work for 10 hours a day to complete the work in 5 days