Math, asked by premthiru, 4 months ago

1/(a^log a base b) has a value of​

Answers

Answered by ThunderShyam
0

Answer:

1/a^log a to base b

log a to base b = log c to a/log c to b (changing the base )

C is of your choice mostly c=10 or e =1

Put log a to base b = m

Now 1/ a^m

Now take logarithm both side

log 1 -- log (a^m)

0 — m log a

0– log a to base b log a

0– log e to a/ log e to b log a

Data is insufficient

Step-by-step explanation:

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