Question

1. A man leaves home for a cycle ride and comes back home after an half-an-hour ride covering a distance of one km. What is the average velocity of the ride

(a) 10 km
(b) 1/2 km/s
(c) 2 km/s
(d) zero

Physics (class 11)
MCQ ​

Answer 1

The average velocity is zero

Given:

A man leaves home for a cycle ride and comes back home after a half-an-hour rise covering a distance of 1 km.

To find:

The average velocity

$\boxed{\red{Average\ velocity(\bar{v})=\frac{x_{2}-x_{1}}{t_{2}-t_{1}}=\frac{\triangle x}{\triangle t}}}$

• Average velocity: The change in position or displacement divided by the time intervals.

Here,

• (x₁) and (x₂) is the position of the object at the time (t₁) and (t₂) accordingly.
• (Δx) = displacement and (Δt) = time interval.

The man comes back home. So, displacement is 0 and time take = 1/2 hour

$Average\ velocity(\bar{v})=\dfrac{0}{(\frac{1}{2})} = 0$

Thus, option (d) zero is correct

• The average velocity of the ride is zero

Answer 2

Distance = 1 km

Time taken = 0.5 hours

Displacement = 0 km

As the man comes back to home (initial position), hence the initial position and final position are same. Thus displacement is zero.

$\boxed{ \rm{Velocity = \frac{ Displacement}{ Time \: taken}}}$

$\sf Velocity = \dfrac{0}{0.5}$

$\therefore \: \sf \underline {Velocity = 0 \: km {h}^{ - 1} }$

$\large \therefore \underline{ \sf {Answer = (d) Zero}}$