Question

1. A motor bike, initially at rest, picks up a velocity of 72 kmh-over a distance of 40 m. Calculate
(1) acceleration (ii) time in which it picks up above velocity.
[(1) 5 ms (ii) 4 s)
2. A cyclist driving at 5 msl nicks a velocity of 10 ms-1
ar
distond​

Answer 1

Answer:

b 4 s

Explanation:

u=0

v=72km/m=72×5/18 = 20m/s

v²= u²+2as

20×20=0+2×40×a

a=5m/s²

v=u+at

20−0=at

t=4sec