Question

1.a number when divided by 143 leaves 31 as remainder. what will be the remainder when the same number is divided by 13 2. if a and b are positive integers such that a = x^3y^2 and b=xy^3, where x and,y are prime numbers, then HCF(a,b)=? 3.if pand q are positive integers such that a=p=ab^2 and q=a^3b, where a and b are prime no., then LCM(p,q)=?

Answer 1

1- 174/143 = 1 (with remainder 31)
174/13 = 13 and remainder = 5

2- hcf = xy^2

3 - lcm = a^3b^q