Question

1) A pair of bullocks exert a force of 140 N on a plough. The field being ploughed is 15 m long. How much work is done in ploughing the length of the field ?​

Answer 1

Given :

• force exerted by bullocks, F = 140 N
• displacement by the bullock, S = 15 m

To find :

• work done by the bullocks for ploughing the field, W = ?

Formula required :

Formula to calculate work done

     work done = Force × displacement

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• Work is defined as the energy transferred when a force is applied on the body to cover a displacement.
• When the force applied is along the direction of displacement of body then work done is simply calculated by the product of force and displacement. ( W = F × S )
• When Force is applied at an angle of θ to the displacement then; W = F × S × cos θ
• Work is a scalar quantity.
• SI unit of work is Joule
• Dimensions of Work [M L² T⁻²]

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Calculation :

Using formula to calculate work

→ W = F × S

→ W = ( 140 ) × ( 15 )

→ W = 2100 Joules

therefore,

• Work done for ploughing the field is 2100 Joules .

Answer 2

Answer:-

Given:-

• Force exerted by the bullocks (F) = 140 N
• Field ploughed (Let it be the displacement) = 15 m

To Find: Work done by the bullock.

We know,

$\boxed{\sf{W = F × s}}$

where,

• W = Work done,
• F = Force exerted,
• s = Displacement.

∴ W = (140 N)(15 m)

⇢ W = 2100 N m

⇢ W = 2100 J

REQUIRED ANSWER:-

➯ Therefore, work done by the bullocks was of 2,100 Joules.