Question

1.
A particle is subjected to two S H Ms
X, = A, sin wt and x, = A, sin (wt + /4). The
resultant SHM will have an amplitude of
1)
Ai+A2 2 √Ai+A
22
3)A+ Az + V2A, A, 4)A,A,​

Answer 1

Answer:

solved

Explanation:

x1 = A sin wt

x2 = A sin (wt + π/4) = A/√2 sin wt + A/√2 cos wt

x1 + x2 = A(2 + √2)/2 sin wt + A√2/2 cos wt

resultant Amplitude = A√(2+√2)