Question

1. A path of uniform width surrounds a circular park. The difference of internal and external circumferences of this circular path is 132 metres. Its width is: (Take π =22/7)
(1) 22 m
(2) 20 m
(3) 21 m
(4) 24 m

Answer 1

Hey there !!!!!!!

If R is the external radius and r is the internal radius 

the difference between the external and internal radius will be the width of circular park.

R-r =width

Now 

External circumference- internal circumference = 132

2πR-2πr=132

2π(R-r)=132

But R-r = width 

2π*width=132

π*width= 66

width =66/π =66/22/7 =66*7/22 =3*7 =21m

Hope this helped you ........

Answer 2

Answer:

21 m

Step-by-step explanation:

we can imagine that R is external radius and r is internal radius

the difference between external and internal radius is width of circular path

External circumference - internal circumference = 132 m

2πR-2πr = 132 m

taking 2π as common

2π(R-r) = 132 m

but (R-r)= width

substituting width we get

2π× width= 132 m

π× width = 132/2

π × width = 66 m

width = 66/π

= 66/22/7

by solving this we get

66×7/22 = 3×7 = 21 m

hope this help u