Question

1) A plane flies 120km due north, and then heads due east for 80km. How far is the plane from its starting point?

Answer 1

Answer:

40√13km

Step-by-step explanation:

total displacement = √(120²+80²) = 40√13km

and tan∅ = 120/80 = 3/2

or ∅ = tan^(-1)[3/2]

hence the aeroplane is at a distance of 40√13km from its initial position in a direction of tan^(-1)[3/2] North of East