Question

1.
A projectile is fired horizontally with a
velocity of 90ms from top of a hill
500m high. If g= 10 ms 2, the lorizontal
distance from the foot of the hill where
the projectile will strike the ground is
a) 90m
b) 900 m
c) 500m
d)50m​

Answer 1

Answer:

u = 90m/s

h = 500m

g = 10m/s²

Vertical height

Sy= Uyt + 1/2 gyt²

500 = (0 × t) + 1/2 (10t²)

2×500=10t²

1000=10t²

1000/10 = t²

√100 = t

t = 10

Horizontal range

Sx = Uxt + 1/2 gxt²

Sx =Uxt + 0

Sx = 90 × 10

Sx = 900m

Thankyou...

Answer 2

Answer:

A projectile is fired horizontally with a

velocity of 90ms from top of a hill

500m high. If g= 10 ms 2, the lorizontal

distance from the foot of the hill where

the projectile will strike the ground is

a) 90m

b) 900 m☑️

c) 500m

d)50m