Physics, asked by satyamsn0537, 3 days ago

-1
A proton moving with a
velocity of 2x109 ms
describes a circle of
radius R in a magnetic
field. The speed of an a-
particle to describe a
circle of same radius in
the same magnetic field
is​

Answers

Answered by ekansh71
0

Answer:

r=

qB

mv

For proton

r

p

=

eB

m×2×10

6

for α− particle

r

α

=

2eB

4m×V

∵r

p

=r

α

2×10

6

=2V

V=1×10

6

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