Question

1) A rectangle has a width of 9 cm and its diagonal is 41 cm.
Find its perimeter and area.​

Answer 1

Answer:

LET ABCD be the RECTANGLE.

AB=9cm.BC=x cm

AC=41 cm.

IN TRIANGLE ABC,AC^2=AB^2+BC^2

41^2=9^2+x^2

x^2=1681-81

x^2=1600

x=40 cm

PERIMETER =2(AB+BC)=2(49)=98 cm

AREA=AB×BC=9×40=360 cm^2.

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Answer 2

Step-by-step explanation:

perimeter is 98 cm

area is 360 cm^2

the step by step solution is given above.

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