Question

1. A rectangular field is 15 m long and 10 m wide. Another rectangular field having the same perimeter has its sides in the ratio 4 : 1. Find the dimension of the rectangular field.​

Answer 1

Answer:

Length = 20m

Breadth = 5m

Step-by-step explanation:

Perimeter of first field = 2(15+10)

                                    =50m

Let the breadth of another field be x.

• 2(4x+x)=50m
• 10x=50
• x=5

Breadth of field = 5m

length of field = 20m

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Answer 2

★ Solution :-

First, we should find the perimeter of the first rectangular field.

Perimeter of the first field :-

$\sf \leadsto Perimetre_{(Rectangle)} = 2 \: (Length + Breadth)$

$\sf \leadsto P = 2 \: (15 + 10)$

$\sf \leadsto P = 2 \: (25)$

$\sf \leadsto P = 50 \: m$

Now, we can find the dimensions of the second rectangle.

$\sf \leadsto Perimetre_{(Rectangle)} = 2 \: (Length + Breadth)$

$\sf \leadsto 50 = 2 \: (4x + 1x)$

$\sf \leadsto 50 = 2 \: (5x)$

$\sf \leadsto \dfrac{50}{2} = 5x$

$\sf \leadsto 25 = 5x$

$\sf \leadsto x = \dfrac{25}{5}$

$\sf \leadsto x = 5$

Length of the rectangle :-

$\sf \leadsto 4x = 4(5)$

$\sf \leadsto Length = 20 \: metres$

Breadth of the rectangle :-

$\sf \leadsto 1x = 1(5)$

$\sf \leadsto Breadth = 5 \: metres$

Hence, the length and breadth of the rectangular field are 20 and 5 metres respectively.