Question

1.A regular pentagon ABCDE and a square ABFG
are formed on opposite sides of AB. Find ZBCF.
2.In a parallelogram ABCD, the angle bisector of;
ZA bisects BC. Will angle bisector of ZB also
bisects AD? Give reason.​

Answer 1

Hlo mate here is ur ans......

Now angle FBA = 90

angle ABC = 108

By sum of all angles at a point angle

FBC = 162

Also triangle FBC is isosceles triangle soo angle BFC = 1/2(180 - angle FBC)

SOOOOOO angle BFC = 9 Degree......

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