Question

1. A's income is 10% less than that of B. By what per cent is B's income more than A's?​

Answer 1

Answer:

$11 \ \frac{1}{9}$

Step-by-step explanation:

Let the income of B be x

So, the income of A = x - x × 10/100

= x - 1x/10

= 9x/10

More income by = x - 9x/10

= x/10

More income in % = x/10 × 100 × 10/9x

= 100/9 %

Answer 2

11.11 %

Let income of B is X

Income of A will be X-(10% X)= 0.9* X

Now question is what percentage of B's income is more than A's income so formula is

(B's income - A's income)/ A's income

Therefore,

((X - 0.9*X)/0.9*X)*100

= (0.1/0.9)*100

=11.11%