1. A steady current of 10 MA flows through a circuit for half an hour find out the amount of charge transferred during this time?
2.A nickel wire has diameter 1mm and restivity 0.8 × 10-⁸ ohm what will be the length of wire to make its resistance 5 ohm
Answers
Answered by
0
1. I suppose you meant 1mA, please be very careful in writing units, mA means milli Amperes, MA means Mega Amperes, which is very unusual. So the answer below assumes mA or milli amperes.
1 Ampere = 1 Coulomb per 1 second, so if 1 Ampere flows for 1 second, charge transferred is 1 Coulomb
For given problem, current = 1 * 10^-3 Amperes
Time = 30 * 60 = 1,800 seconds
so Charge = 1 * 10 ^-3 * 1800
= 1.8 Coulombs ... Answer
2. Resistance = Rho * l / A (Rho = resistivity, l = length, A = Area)
So Length l - R * A / Rho
= 5 * / 0.8 * 10^-8
= 4.91 * 10^8 mm
= 491 km.. Answer
1 Ampere = 1 Coulomb per 1 second, so if 1 Ampere flows for 1 second, charge transferred is 1 Coulomb
For given problem, current = 1 * 10^-3 Amperes
Time = 30 * 60 = 1,800 seconds
so Charge = 1 * 10 ^-3 * 1800
= 1.8 Coulombs ... Answer
2. Resistance = Rho * l / A (Rho = resistivity, l = length, A = Area)
So Length l - R * A / Rho
= 5 * / 0.8 * 10^-8
= 4.91 * 10^8 mm
= 491 km.. Answer
Answered by
0
1. I suppose you meant 1mA, please be very careful in writing units, mA means milli Amperes, MA means Mega Amperes, which is very unusual. So the answer below assumes mA or milli amperes.
1 Ampere = 1 Coulomb per 1 second, so if 1 Ampere flows for 1 second, charge transferred is 1 Coulomb
For given problem, current = 1 * 10^-3 Amperes
Time = 30 * 60 = 1,800 seconds
so Charge = 1 * 10 ^-3 * 1800
= 1.8 Coulombs ... Answer
Similar questions
Social Sciences,
8 months ago
English,
8 months ago
Environmental Sciences,
8 months ago
Environmental Sciences,
1 year ago
English,
1 year ago