Physics, asked by KSA, 1 year ago



1. A steady current of 10 MA flows through a circuit for half an hour find out the amount of charge transferred during this time?
2.A nickel wire has diameter 1mm and restivity 0.8 × 10-⁸ ohm what will be the length of wire to make its resistance 5 ohm

Answers

Answered by sundaramkrs
0
1. I suppose you meant 1mA, please be very careful in writing units, mA means milli Amperes, MA means Mega Amperes, which is very unusual. So the answer below assumes mA or milli amperes.

1 Ampere = 1 Coulomb per 1 second, so if 1 Ampere flows for 1 second, charge transferred is 1 Coulomb

For given problem, current = 1 * 10^-3 Amperes
Time = 30 * 60 = 1,800 seconds
so Charge = 1 * 10 ^-3 * 1800
= 1.8 Coulombs ... Answer

2. Resistance = Rho * l / A (Rho = resistivity, l = length, A = Area)
So Length l - R * A / Rho
= 5 *  \pi * 1 ^2 / 4 / 0.8 * 10^-8
= 4.91 * 10^8 mm
= 491 km.. Answer


Answered by Anonymous
0

1. I suppose you meant 1mA, please be very careful in writing units, mA means milli Amperes, MA means Mega Amperes, which is very unusual. So the answer below assumes mA or milli amperes.

1 Ampere = 1 Coulomb per 1 second, so if 1 Ampere flows for 1 second, charge transferred is 1 Coulomb

For given problem, current = 1 * 10^-3 Amperes

Time = 30 * 60 = 1,800 seconds

so Charge = 1 * 10 ^-3 * 1800

= 1.8 Coulombs ... Answer

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