Question

1. A street lane is to be paved with tiles of length 12 cm and breadth 10 cm. If the length
of the lane is 240 m and its breadth is 12 m, find the number of tiles needed.
If the length and breadth are taken always in natural numbers, find the same in each case


0.5
10.5
0.5
1.5
1.5
A 2
2
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HOTS
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NOW
1.
2. A wire of length 20 cm is to be bent to form a rectangle of
(i) maximum area
(i) minimum area
case.
​

Answer 1

$answer$

1))Area of Tiles= 12*10= 12cm^{2}

Area of the Lane= 240*12= 2880m^{2}

= 2880*10000= 28800000cm^{2}

No. of Tiles required= Area of Lane/ Area of Tiles= 28800000/12= 24,00,000 tiles

Answer 2

Answer:

Step-by-step explanation: Total area of the street lane= 240(12) m^2

                                                                                            =2880m^2

                                                                                            28800000 cm^2

Total area of each tile is 120 cm^2

So, no of tiles required is 28800000/120 =240000