1. A thief, after committing a theft runs at a uniform speed of 50 m/minute. After 2 minutes,
a policeman runs to catch him. He goes 60 m in first minute and increases his speed by
5 m/minute every suceeding minute. After how many minutes, the policeman will catch
the thief?
Answers
Step-by-step explanation:
as thief covers dist in 1min is 50m so in 2 mins he cover 100.. and police man runs after him to catch him .....
nice question
plz mark it as brainliest one
Answer:
According to the question,
Distance between thief and police after 2 minutes = 100 m
Police starts chasing thief with initial speed of 60 and increasing his speed by 5 m every minute.
Let the police chase the thief for t minutes.
Implies, thief covers total 100 + 50t m
Police runs with following pattern 60,65,70...
This is an Arithmetic Progression with a = 60, d = 5 & number of terms = t
t/2(2×60+(t−1)×5)=50t+100
t×(120+5t−5)=100t+200
5t
2
+15t−200=0
t
2
+3t−40=0
t={−3±
(9+160)}/2
=(−3±13)/2=+5
Implies, police will catch thief in 5 minutes. or thief will be caught by police in 7 minutes.