Find the altitude of a rhombus, whose area is 50 m2 and perimeter is 60 m
Answers
Answered by
2
PLZ MARK MY SOLUTION AS THE BRAINLIEST.
PERIMETER OF THE RHOMBUS = 60 m.
SO, ITS EACH SIDE = PERIMETER / 4 = 60 / 4 m = 15 m.
AREA OF THE RHOMBUS IS EQUAL TO THE PRODUCT OF BASE AND HEIGHT.
AREA = 50 m ^ 2
BASE = LENGTH OF EACH SIDE = 15 m
LET THE HEIGHT BE H m.
SO, BY THE PROBLEM,
15 × H = 50
H = 50/ 15 = 3.34
SO, THE ALTITUDE OF THE RHOMBUS IS 3.34 m.
PERIMETER OF THE RHOMBUS = 60 m.
SO, ITS EACH SIDE = PERIMETER / 4 = 60 / 4 m = 15 m.
AREA OF THE RHOMBUS IS EQUAL TO THE PRODUCT OF BASE AND HEIGHT.
AREA = 50 m ^ 2
BASE = LENGTH OF EACH SIDE = 15 m
LET THE HEIGHT BE H m.
SO, BY THE PROBLEM,
15 × H = 50
H = 50/ 15 = 3.34
SO, THE ALTITUDE OF THE RHOMBUS IS 3.34 m.
Answered by
0
Answer:
find the altitude of rhombus whose area is 15 m square and perimeter is 60 m.
Similar questions